Feb 26, 2021 · The question here is how (if it is even possible) to remove the square root terms and transform the following equation to a polynomial with one unknown $x$. The coefficients $a$, $b$, …

In general, the polynomial relation will have $2^n$ distinct 'roots' for the one non-square-root variable of the original expression in terms of the other variables.

Nov 3, 2016 · Now do the same with the terms involving $\sqrt b$ (even where multiplied by other square roots) to eliminate that. After squaring four times (to deal with $\sqrt c$ and $\sqrt d$ as well), …

Jun 24, 2014 · Square root inside a square root Ask Question Asked 11 years, 5 months ago Modified 4 years, 11 months ago

To get rid of the square roots of the denominator, you may use $a^2-b^2= (a+b) (a-b)$.

May 29, 2014 · Getting rid of square root in this integration Ask Question Asked 11 years, 6 months ago Modified 11 years, 3 months ago

9 The form with neither denominators in radicals nor radicals in denominators and with only squarefree expressions under square-root signs, etc., is a canonical form, and two expressions are equal …

Sep 1, 2016 · If you start by solving the equation this way, you will eventually complete the square and get an answer of: $$4$$ However, why must the radical be isolated before squaring both sides?

Minor point: I notice quite a few elementary algebra books as well as some writers here taking the view that the n-th root of x is defined as x to the power 1/n. I disagree strongly. For an elementary student, …

Nov 17, 2013 · A slightly higher-level way to phrase the issue is that the usual square root is not a "function" at all. "Doing the same thing" to both sides only preserves equality if "doing the same …